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5x^2-33x+8=0
a = 5; b = -33; c = +8;
Δ = b2-4ac
Δ = -332-4·5·8
Δ = 929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-\sqrt{929}}{2*5}=\frac{33-\sqrt{929}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+\sqrt{929}}{2*5}=\frac{33+\sqrt{929}}{10} $
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